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Strip Out Weekend dates - user defined function

VB icon
Submitted on: 12/11/2003 10:03:25 AM
By: Paul D Brower 
Level: Advanced
User Rating: Unrated
Compatibility:SQL Server 2000

Users have accessed this code 519 times.
     Allows you to get an accurate count of weekdays for a given date range.
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-- for :Strip Out Weekend dates - user d
--     efined function
feel free TO use, just don't strip out my info
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By using this code, you agree to the following terms...   
1) You may use this code in your own programs (and may compile it into a program and distribute it in compiled format for languages that allow it) freely and with no charge.   
2) You MAY NOT redistribute this code (for example to a web site) without written permission from the original author. Failure to do so is a violation of copyright laws.   
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-- Name: Strip Out Weekend dates - user 
--     defined function
-- Description:Allows you to get an accu
--     rate count of weekdays for a given date 
--     range.
-- By: Paul D Brower
-- Inputs:Starting Date, Ending Date
-- Returns:Integer
--This code is copyrighted and has-- limited warranties.Please see http://
--     www.Planet-Source-Code.com/vb/scripts/Sh
--     owCode.asp?txtCodeId=790&lngWId;=5--for details.--**************************************

CREATE FUNCTION fn_WeekEndDays (@StartDate datetime, @EndDate datetime)
-- *************************************
--     ****************************************
--     ***************
-- 12-10-2003
-- Pass in two dates, and the function w
--     ill return the number of weed-end days 
-- 	between the two dates, including the
--      two dates
--     -15-03')
-- *************************************
--     ****************************************
--     ***************
    DECLARE @tDate datetime
    DECLARE @intDays int
    SET @intDays = 0
    SET @tDate = @StartDate
    WHILE @tDate <= @EndDate
    		IF (SELECT DATEPART(DW,@tDate)) = 1
    				SET @intDays = @intDays + 1
    		IF (SELECT DATEPART(DW,@tDate)) = 7
    				SET @intDays = @intDays + 1
    		SET @tDate = @tDate + 1
    RETURN @IntDays

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