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Show Bid Request

a number function
Bid Request Id: 61292
Bookmark in my 'To Do' list
Posted by: A. Walter (64 ratings)
(Software buyer rating 10)
Non-action Ratio: Above Average - 26.72%
Buyer Security Verifications: Excellent
Approved on: May 4, 2003
12:20:17 PM EDT
Bidding Closes: May 5, 2003
1:19:37 PM EDT
Viewed (by coders): 195 times
Deadline: 5/6/2003
TIME EXPIRED
Phase:
100% of work was accepted by buyer. Coder account has been credited.
Max Accepted Bid: Bidding is closed
Project Type: Personal Project / Homework Help
Bidding Type: Open Auction
Categories: Windows, Visual Basic
Enter chat room for this bid request
(0 active users at Sep 1, 2003 9:13:01 AM EDT)

Description:
I need a function built where the parameters would be the number chosen and the multiplier. Here is an example. If the number chosen is one and the multiplier is 3, then the function would return 1. The same with 2 or 3. However, if the number chosen is four and the multiplier is 3, then it would return 2 because from 1 to the number is 1 and that number +1 plus number - 1 would be 2, etc. Here is an example of the first three assuming multiplier is 4
if chosen was 1 to 4 then return 1
if chosen was 5 to 8 then return 2
if chosen was 9 to 12 then return 3
Another example where multiplier is 3
1 to 3=1
4 to 6=2
7 to 9=3
The formula chosen/multiplier almost works.
However, the only problem is it rounds numbers. This is not correct. If there is a way to force it to not round, then this would be perfect. Otherwise, there needs to be another way. I would prefer it to force it to not round if possible since that would be the simpliest formula.

Deliverables:
The completed function to show the number function with no rounding (if not possible, then using a different formula or series of formulas). For the project just use these two lines of code for the main procedure
dim numberfunction as integer
numberfunction(1, 3)
msgbox newnumber
this name can be whatever name you want to call for the function.
where 1 equals the chosen and 3 equals the multiplier. I may change the values so it must work consistent no matter what numbers are chosen assuming integer variable type (will never needs numbers beyond 33167 for example.)
The message box will show the it gives the correct number. This needs to be completed within 24 hours of accepting the bid at the most.



Platform:
Windows 98, Windows 2000, Windows XP

Must be 100% finished and received by buyer on:
May 6, 2003 EDT
Deadline legal notes: All times are expressed in the time zone of the site EDT (UT - 5). If the buyer omitted a time, then the deadline is 11:59:59 PM EDT on the indicated date.


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See all rejected bids (and all comments)
Name   Bid Amount 
 
Date   Coder Rating  
This bid was accepted by the buyer!
LARK SOFTWARE
(3 ratings)
in DEVA, HUNEDOARA
Romania
Bid id: 658,096
 
$4 (USD) May 4, 2003
1:48:26 PM EDT
 10
(Excellent)
   
If you consider this code is what you want than consider us the winners and don't forget to give us a 10 rate. We look forward to work with you on other projects.
A bonus will be appreciated as well.

Dim number As Integer
Dim multiplier As Integer

Function f(n As Integer, m As Integer) As Integer
If n Mod m = 0 Then
f = n / m
Else
f = Int(n / m) + 1
End If
End Function

Private Sub Form_Load()
number = 8
multiplier = 3
MsgBox f(number, multiplier)
End Sub

Regards,
Cozmin Tircob

LARK COMPUTERS SRL
 




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